Gas molecules move in random directions with varying speeds, constantly colliding with each other and container walls.
Pressure results from the force of molecular collisions against container walls. More collisions or faster molecules means higher pressure.
Higher temperature means molecules move faster on average. The color coding shows this: blue (cold/slow) to red (hot/fast).
Temperature (in Kelvin) is directly proportional to average kinetic energy: T ∝ KE. Double the temperature, double the average KE.
Reducing volume at constant temperature increases collision frequency with walls, raising pressure.
This graph shows how kinetic energy relates to temperature in Celsius. Notice that at -273.15°C (absolute zero), the kinetic energy reaches its minimum.
When we use the Kelvin scale, we see a beautiful direct proportionality between temperature and kinetic energy, starting from absolute zero at 0 K.
Absolute zero (-273.15°C or 0 K) is the lowest possible temperature. At this point, molecules have minimum kinetic energy (they don't stop completely due to quantum mechanics, but their motion is minimal). It's impossible to reach absolute zero in practice, but it serves as the zero point for the Kelvin scale.
The Kelvin scale starts at absolute zero (0 K), making it ideal for scientific calculations. Temperature in Kelvin is directly proportional to average kinetic energy: if you double the Kelvin temperature, you double the average KE. This simple relationship doesn't work with Celsius!
Water freezes: 0°C = 273.15 K
Water boils: 100°C = 373.15 K
Room temperature: 25°C = 298.15 K
Absolute zero: -273.15°C = 0 K
Problem: A gas has a volume of 250 cm³ at 100 kPa. What is the pressure if the volume is compressed to 100 cm³ at constant temperature?
Solution:
Given: P₁ = 100 kPa, V₁ = 250 cm³, V₂ = 100 cm³
Using P₁V₁ = P₂V₂:
P₂ = (P₁ × V₁) / V₂ = (100 × 250) / 100 = 250 kPa
Answer: The pressure increases to 250 kPa
Problem: A gas has a pressure of 150 kPa at 300 K. What is the pressure if heated to 600 K at constant volume?
Solution:
Given: P₁ = 150 kPa, T₁ = 300 K, T₂ = 600 K
Using P₁/T₁ = P₂/T₂:
P₂ = (P₁ × T₂) / T₁ = (150 × 600) / 300 = 300 kPa
Answer: The pressure doubles to 300 kPa (because temperature doubled)